Answer
TRUE
Work Step by Step
Since the index ($3$) is odd, then for any real number, $\sqrt[3]{a^3}=a.$ Hence the given statement is $\text{
TRUE
.}$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 693: 4
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
