Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 11

Answer

$f(15)=5$

Work Step by Step

Substituting $x=15$ in the given function, $ f(x)=\sqrt{x+10} ,$ then \begin{array}{l}\require{cancel} f(x)=\sqrt{x+10} \\\\ f(15)=\sqrt{15+10} \\\\ f(15)=\sqrt{25} \\\\ f(15)=\sqrt{(5)^2} \\\\ f(15)=5 .\end{array}
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