Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 77

Answer

9000 = 9 $\times$ $10^{3}$

Work Step by Step

We need to write 9000 as the product of a number greater than or equal to 1 and less than 10 and an integer power of 10. The number greater than or equal to 1 and less than 10 will be 9. The decimal point has moved 3 places, so the exponent of 10 will be 3. So, 9000 = 9 $\times$ $10^{3}$
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