Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set - Page 231: 65



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{24a^5}{3a^{-1}} ,$ simplifies to \begin{array}{l}\require{cancel} (24\div3)a^{5-(-1)} \\\\= 8a^{5+1} \\\\= 8a^{6} .\end{array}
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