Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 65

Answer

$8a^{6}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{24a^5}{3a^{-1}} ,$ simplifies to \begin{array}{l}\require{cancel} (24\div3)a^{5-(-1)} \\\\= 8a^{5+1} \\\\= 8a^{6} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.