## Elementary Algebra

$7a^3b^4$
We use the rules of exponents to obtain: $\frac{-56a^5b^7}{-8a^2b^3}=\frac{-56}{-8}\times\frac{a^5}{a^2}\times\frac{b^7}{b^3}=7\times a^{5-2}\times b^{7-3}=7a^3b^4$