Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 66

Answer

$\dfrac{4}{n}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{48n^{-2}}{12n^{-1}} ,$ simplifies to \begin{array}{l}\require{cancel} (48\div12)n^{-2-(-1)} \\\\= 4n^{-2+1} \\\\= 4n^{-1} \\\\= \dfrac{4}{n^1} \\\\= \dfrac{4}{n} .\end{array}
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