Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 55

Answer

$\dfrac{16}{9}$

Work Step by Step

Using $a^{-x}=\dfrac{1}{a^x}$, the given expression, $ \left( \dfrac{3}{4} \right)^{-2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{\left( \dfrac{3}{4} \right)^2} \\\\= \dfrac{1}{\dfrac{9}{16}} \\\\= 1\div\dfrac{9}{16} \\\\= 1\cdot\dfrac{16}{9} \\\\= \dfrac{16}{9} .\end{array}
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