Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 67

Answer

$\dfrac{x^{2}}{y}$

Work Step by Step

Using the laws of exponents, the given expression, $ (x^{-2}y)^{-1} ,$ simplifies to \begin{array}{l}\require{cancel} x^{-2(-1)}y^{1(-1)} \\\\= x^{2}y^{-1} \\\\= \dfrac{x^{2}}{y^1} \\\\= \dfrac{x^{2}}{y} .\end{array}
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