Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 66

Answer

$\dfrac{1}{8n^6}$

Work Step by Step

Using the laws of exponents, the given expression, $ (2n^{2})^{-3} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{-3}n^{2(-3)} \\\\= 2^{-3}n^{-6} \\\\= \dfrac{1}{2^3n^6} \\\\= \dfrac{1}{8n^6} .\end{array}
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