Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 25



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{10^{-1}}{10^{2}} ,$ is equivalent to \begin{array}{l}\require{cancel} 10^{-1-2} \\\\= 10^{-3} \\\\= \dfrac{1}{10^3} \\\\= \dfrac{1}{1,000} .\end{array}
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