# Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6 - Page 223: 19

$\dfrac{1}{8}$

#### Work Step by Step

Using the laws of exponents, the given expression, $2^6\cdot2^{-9} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{6+(-9)} \\\\= 2^{-3} \\\\= \dfrac{1}{2^3} \\\\= \dfrac{1}{8} .\end{array}

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