Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 26

Answer

$1$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{10^{-2}}{10^{-2}} ,$ is equivalent to \begin{array}{l}\require{cancel} 10^{-2-(-2)} \\\\= 10^{-2+2} \\\\= 10^0 \\\\= 1 .\end{array}
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