Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 22

Answer

$\dfrac{1}{32}$

Work Step by Step

Using the laws of exponents, the given expression, $ 2^{-7}\cdot2^{2} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{-7+2} \\\\= 2^{-5} \\\\= \dfrac{1}{2^5} \\\\= \dfrac{1}{32} .\end{array}
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