Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 27

Answer

$18$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( 2^{-1}\cdot3^{-2} \right)^{-1} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{-1(-1)}\cdot3^{-2(-1)} \\\\= 2^{1}\cdot3^{2} \\\\= 2\cdot9 \\\\= 18 .\end{array}
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