Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6 - Page 223: 28

Answer

$48$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( 3^{-1}\cdot4^{-2} \right)^{-1} ,$ is equivalent to \begin{array}{l}\require{cancel} 3^{-1(-1)}\cdot4^{-2(-1)} \\\\= 3^{1}\cdot4^{2} \\\\= 3\cdot16 \\\\= 48 .\end{array}
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