## Elementary Algebra

$t=\dfrac{5}{21}$
Using the properties of equality, the value of the variable that satisfies the given equation, $3(2t-4)+2(3t+1)=-2(4t+3)-(t-1) ,$ is \begin{array}{l}\require{cancel} 6t-12+6t+2=-8t-6-t+1 \\\\ 6t+6t+8t+t=-6+1+12-2 \\\\ 21t=5 \\\\ t=\dfrac{5}{21} .\end{array}