Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 137: 24



Work Step by Step

Substituting $F=77$in the given equation, $ F=\dfrac{9}{5}C+32 ,$ we obtain: \begin{array}{l}\require{cancel} 77=\dfrac{9}{5}C+32 \\\\ 77-32=\dfrac{9}{5}C \\\\ 45=\dfrac{9}{5}C \\\\ \dfrac{5}{9}\cdot45=\dfrac{9}{5}C\cdot\dfrac{5}{9} \\\\ \dfrac{5}{\cancel{9}}\cdot\cancel{9}(5)=C \\\\ C=25 .\end{array}
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