Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 137: 16



Work Step by Step

Multiplying both sides by the $LCD= 72 $ and using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{x-3}{9}=\dfrac{x+4}{8} ,$ is \begin{array}{l}\require{cancel} 8(x-3)=9(x+4) \\\\ 8x-24=9x+36 \\\\ 8x-9x=36+24 \\\\ -x=60 \\\\ x=-60 .\end{array}
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