## Elementary Algebra

$n=21$
Using the properties of equality, the value of the variable that satisfies the given equation, $5(n-1)-4(n+2)=-3(n-1)+3n+5 ,$ is \begin{array}{l}\require{cancel} 5n-5-4n-8=-3n+3+3n+5 \\\\ 5n-4n+3n-3n=3+5+5+8 \\\\ n=21 .\end{array}