Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 137: 17



Work Step by Step

Multiplying both sides by the $LCD= -12 $ and using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{x-1}{-3}=\dfrac{x+2}{-4} ,$ is \begin{array}{l}\require{cancel} 4(x-1)=3(x+2) \\\\ 4x-4=3x+6 \\\\ 4x-3x=6+4 \\\\ x=10 .\end{array}
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