Answer
$F(x)= H(x)-3 G(x)+2 J(x)$
Therefore, $D^3(D-4)^2$ is the annihilator of $F(x)$.
Work Step by Step
Since, $(D-4)^2$ is the annihilator of $G(x)= xe^{4x}$
Also, we have: $(D-4)^2$ is the annihilator of $H(x)=e^{4x}$.This implies that the $(D-4)^2$ is the annihilator of $H(x)-3G(x)=e^{4x}-3xe^{4x}$
So, $F(x)= H(x)-3 G(x)+2 J(x)$
Therefore, $D^3(D-4)^2$ is the annihilator of $F(x)$.