Answer
$F(x)=4G(x)$
Therefore, $D^2+4r+5$ is the annihilator of $F(x)$.
Work Step by Step
We are given that $D^2+4r+5$ is the annihilator of $G(x)= e^{-2x} \sin x$
So, $F(x)=4G(x)$
Therefore, $D^2+4r+5$ is the annihilator of $F(x)$.
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