Answer
See answers below
Work Step by Step
$\begin{bmatrix}
-4 & 2\\
-6& 3
\end{bmatrix} \approx^1 \begin{bmatrix}
1 & -\frac{1}{2}\\
-6& 3
\end{bmatrix} \approx^2\begin{bmatrix}
1 & -\frac{1}{2}\\
0& 0
\end{bmatrix}$
Rank (A)= 1
The last matrix is in a row-echelon form.
$M_1(-\frac{1}{4})$
$A_{12}(6)$
