College Algebra 7th Edition

$\frac{y-2}{3-y}$
We factor out $y$ and simplify: $\displaystyle \frac{1-\frac{2}{y}}{\frac{3}{y}-1}=\frac{y(1-\frac{2}{y})}{y(\frac{3}{y}-1)}=\frac{y-2}{3-y}$