College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 61

Answer

$\frac{x+3}{x+1}$

Work Step by Step

We multiply the numerator and denominator by $x+2$, then simplify: $\displaystyle \frac{1+\frac{1}{x+2}}{1-\frac{1}{x+2}}=\frac{(x+2)(1+\frac{1}{x+2})}{(x+2)(1-\frac{1}{x+2})}=\frac{(x+2)+1}{(x+2)-1}=\frac{x+3}{x+1}$
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