College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 52

Answer

$\frac{2(x+1)}{(x-2)(x+2)}$

Work Step by Step

We form a common denominator, then add, factor, and simplify: $\displaystyle \frac{x}{x^{2}-4}+\frac{1}{x-2}=\frac{x}{(x-2)(x+2)}+\frac{1}{x-2}=\frac{x}{(x-2)(x+2)}+\frac{x+2}{(x-2)(x+2)} =\frac{2x+2}{(x-2)(x+2)}=\frac{2(x+1)}{(x-2)(x+2)}$
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