College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 53



Work Step by Step

We form a common denominator, then add, factor, and simplify: $\displaystyle \frac{1}{x+3}+\frac{1}{x^{2}-9}=\frac{1}{x+3}+\frac{1}{(x-3)(x+3)}=\frac{x-3}{(x-3)(x+3)}+\frac{1}{(x-3)(x+3)}=\frac{x-2}{(x-3)(x+3)}$
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