## College Algebra 7th Edition

Published by Brooks Cole

# Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 53

#### Answer

$\frac{x-2}{(x-3)(x+3)}$

#### Work Step by Step

We form a common denominator, then add, factor, and simplify: $\displaystyle \frac{1}{x+3}+\frac{1}{x^{2}-9}=\frac{1}{x+3}+\frac{1}{(x-3)(x+3)}=\frac{x-3}{(x-3)(x+3)}+\frac{1}{(x-3)(x+3)}=\frac{x-2}{(x-3)(x+3)}$

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