## College Algebra 7th Edition

$\frac{2(5x-9)}{(2x-3)^{2}}$
We form a common denominator: $\displaystyle \frac{5}{2x-3}-\frac{3}{(2x-3)^{2}}=\frac{5(2x-3)}{(2x-3)^{2}}-\frac{3}{(2x-3)^{2}}=\frac{10x-15-3}{(2x-3)^{2}}=\frac{10x-18}{(2x-3)^{2}}=\frac{2(5x-9)}{(2x-3)^{2}}$