College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 44

Answer

$\frac{x^{2}+3x+12}{(x-4)(x+6)}$

Work Step by Step

We form a common denominator: $\displaystyle \frac{x}{x-4}-\frac{3}{x+6}=\frac{x(x+6)}{(x-4)(x+6)}+\frac{-3(x-4)}{(x-4)(x+6)}=\frac{x^{2}+6x-3x+12}{(x-4)(x+6)}=\frac{x^{2}+3x+12}{(x-4)(x+6)}$
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