Answer
$\sum_{k=1}^{10}(3k-1)$
Work Step by Step
We write the sum in sigma notation:
(We notice that the terms are multiples of $3$ minus $1$.)
$2+5+8+...+29=\sum_{k=1}^{10}(3k-1)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 601: 68
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