Answer
8
Work Step by Step
We evaluate the sum:
$\sum_{i=1}^{8}[1+(-1)^{i}]=[1-1]+[1+1]+[1-1]+[1+1]+[1-1]+[1+1]+[1-1]+[1+1]=0+2+0+2+0+2+0+2=8$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 601: 51
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