Answer
$1^{3}+2^{3}+3^{3}+4^{3}=1+8+27+64=100$
Work Step by Step
We expand the sum:
$\sum_{k=1}^{4}k^{3}=1^{3}+2^{3}+3^{3}+4^{3}=1+8+27+64$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 601: 61
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