Answer
$\frac{11}{6}$
Work Step by Step
We evaluate the sum:
$\sum_{k=1}^{3} \frac{1}{k}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}=\frac{6}{6}+\frac{3}{6}+\frac{2}{6}=\frac{11}{6}$
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