Answer
$54+70+88+108=320$
Work Step by Step
We expand the sum: $\sum_{k=6}^{9}k(k+3)=6*9+7*10+8*11+9* 12=54+70+88+108$
(The sum is $320$, however we are not asked to find the sum, but simply write the sum without sigma notation.)
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 601: 64
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