Answer
$(\pm2,1)$
Work Step by Step
Adding $-3$ times the first equation to the second one, we get:
$2y^3=2\\y^3=1\\y=1$
Plugging this back into the first equation, we get:
$x^4+1^3=17\\x^4=16\\x=\pm2$
Hence, the solutions are: $(\pm2,1)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 5, Systems of Equations and Inequalities - Section 5.4 - Systems of Nonlinear Equations - 5.4 Exercises - Page 466: 30
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