Chapter 5, Systems of Equations and Inequalities - Section 5.4 - Systems of Nonlinear Equations - 5.4 Exercises - Page 466: 27

$(\pm\sqrt5,\pm2)$

Adding the two equations, we get: $2x^2=10\\x^2=5\\x=\pm\sqrt5$ Plugging this back into the first equation, we get: $(\pm\sqrt5)^2+y^2=9\\5+y^2=9\\y^2=4\\y=\pm2$ Hence, the solutions are: $(\pm\sqrt5,\pm2)$