Chapter 5, Systems of Equations and Inequalities - Section 5.4 - Systems of Nonlinear Equations - 5.4 Exercises - Page 466: 29

$(\pm3,-0.5)$

Adding twice the first equation to the second one, we get: $8x^2=72\\x^2=9\\x=\pm3$ Plugging this back into the first equation, we get: $2(\pm3)^2-8y^3=19\\18-8y^3=19\\-8y^3=1\\y^3=-1/8\\y=-0.5$ Hence, the solutions are: $(\pm3,-0.5)$