Answer
$(2,0),(-2,0)$
Work Step by Step
Adding the two equations, we get:
$2y=0\\y=0$
Plugging this into the first one, we get:
$4-x^2=0\\x^2=4\\x=\pm2$
Thus the solutions are:
$(2,0),(-2,0)$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 5, Systems of Equations and Inequalities - Section 5.4 - Systems of Nonlinear Equations - 5.4 Exercises - Page 466: 22
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