Answer
The intersection points of the graphs are $(-2,-4)$, $(0,0)$, and $(1,-1)$.
Work Step by Step
From the graph, the equations $x^2+y=0$ and $x^3-2x-y=0$ intersect at the points $(-2,-4)$, $(0,0)$, and $(1,-1)$.
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 5, Systems of Equations and Inequalities - Section 5.4 - Systems of Nonlinear Equations - 5.4 Exercises - Page 466: 17
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