Answer
$\log_{a}\frac{bd^{c}}{s^{r}}$
Work Step by Step
$\log_{a}b+c\log_{a}d-r\log_{a}s=\log_{a}(bd^{c})-\log_{a}(s^{r})=\log_{a}\frac{bd^{c}}{s^{r}}$
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