Answer
$\dfrac{1}{2}$
Work Step by Step
RECALL:
(1) $\log_b{M}+\log_b{N}=\log_b{MN}$
(2) $\log_b{M}−\log_b{N}=\log_b{\frac{M}{N}}$
(3) $\log_b{(b^x)}=x$
(4) $\log_b{b}=1$
Note that $\sqrt{5}=5^{\frac{1}{2}}$. Thus, the given expression is equivalent to:
$=\log_5{(5^{\frac{1}{2}})}$
Use rule (3) above to obtain:
$=\frac{1}{2}$