College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises - Page 395: 54

Answer

$\log_{5}(x+1)$

Work Step by Step

$\log_{5}(x^{2}-1)-\log_{5}(x-1)=\log_{5}((x+1)(x-1))-\log_{5}(x-1)=\log_{5}\frac{(x-1)(x+1)}{x-1}=\log_{5}(x+1)$
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