Answer
$\frac{1}{2}(\ln a+\ln b)=\frac{1}{2}\ln a+\frac{1}{2}\ln b$
Work Step by Step
$\ln\sqrt{ab}=\ln(ab)^{1/2}=\frac{1}{2}\ln ab=\frac{1}{2}(\ln a+\ln b)=\frac{1}{2}\ln a+\frac{1}{2}\ln b$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises - Page 395: 30
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