Answer
$-1$
Work Step by Step
RECALL:
(1) $\log_b{M}+\log_b{N}=\log_b{MN}$
(2) $\log_b{M}−\log_b{N}=\log_b{\frac{M}{N}}$
(3) $\log_b{(b^x)}=x$
(4) $\log_b{b}=1$
Write $27$ as $3^3$ to obtain:
$=-\frac{1}{3}\log_3{(3^3)}$
Use rule (3) above to obtain:
$=-\frac{1}{3} \cdot 3
\\=-1$