Answer
$t=15.4~years$
Work Step by Step
$A=Pe^{rt}$
$r=4.5$% $=0.045$
$A=2P$
$2P=Pe^{0.045t}$
$e^{0.045t}=2$
$\ln e^{0.045t}=\ln2$
$0.045t=\ln2$
$t=\frac{\ln2}{0.045}=15.4$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Exercises - Page 426: 94
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