Answer
(a). $n(t)=1500e^{0.15154t}$
(b).$n(11)=7943.91$
Work Step by Step
The formula for exponentially growing population is, $n(t)=n_0e^{rt}$. Whereas, $n(t)$ is the population after time $t$, $n_0$ is the initial population, $r$ is the rate of growth.
From the graph we can see that $n(0)=1500$, and $n(5)=3200$.
$n(5)=1500e^{r5}=3200$,
$2.1333=e^{5r}$,
$\ln 2.133=5r$,
$r=0.15154$.
(a). $n(t)=1500e^{0.15154t}$
(b).$t=11$,
$n(11)=1500e^{0.15154\times11}=7943.91$
