Answer
Basic
Work Step by Step
We are given:
$[\mathrm{H}^{+}]=1.3\times 10^{-8}$ M
$\mathrm{p}\mathrm{H}_{egg\ whites}=-\log[\mathrm{H}^{+}]=-\log(1.3\times 10^{-8})\approx 7.9$
Since we have pH$\gt7$, the egg whites are basic.
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