College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Exercises - Page 426: 104

Answer

$t=42.972$ minutes

Work Step by Step

Newton's Law Of Cooling states that, If an object has an Initial temperature that is $D_0$ warmer than $T_s$, then at time $t$ the temperature $T(t)$ of the object is modeled by the function $T(t)=T_s+D_0e^{-kt}$. where $k$ is a positive constants depends on the size and type of object. $T(0)=190$, $k=0.0341$, $T(t)=90$, $T_s=60$, $D_0=190-60=130$. $90=60+130e^{-0.0341t},$ $30=130e^{-0.0341t}$, $0.231=e^{-0.0341t}$, $\ln 0.231=-0.0341t$, $t=42.972$ minutes
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