College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Exercises - Page 426: 92

Answer

(a). $A(t)=5664.978$ (b). $t=8.08$ (c). $t=3.96$

Work Step by Step

The formula for periodically compounded interest rate is, $A(t)=P(1+\frac{r}{n})^{nt}$. Whereas, $P$ is the Initial investment, $r$ is the rate, $n$ is a number of times it is compounded. Meanwhile, The formula for continuously compounded interest rate is, $A(t)=Pe^{rt}$. $P=5000$, $r=0.085$, $n=2$ (a). $t=1.5$ $A(t)=5000(1+\frac{0.085}{2})^{2\times1.5}=5664.978$ (b).$7000=5000(1+\frac{0.085}{2})^{2t},$ $1.4=(1.0425)^t,$ $\log 1.4=t\log 1.0425$ $t=8.08$ (c). $A(t)=Pe^{rt}$. $7000=5000e^{0.085t},$. $1.4=e^{0.085t},$. $\ln 1.4=0.085t,$ $t=3.96$
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