College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises - Page 193: 71


Domain: $( \frac{1}{2},\ \infty)$

Work Step by Step

We are given: $f(x)= \frac{(x+1)^{2}}{\sqrt{2x-1}}$ The domain of a function consists of all the values that $x$ is allowed to have. In this case, we can not take the square root of a negative number: $2x-1\ge 0$ $x\ge \frac{1}{2}$ In addition, we can not have division by $0$: $2x-1\ne 0$ $x\ne \frac{1}{2}$ Thus the domain is $( \frac{1}{2},\ \infty)$
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